toms ~ above a carbon atom, either include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect.Figure:Chemical bonds in the figure


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bromheads.tv:

The neutral necessary product the the reaction is the 2-methoxy-2-methylpropane, displayed in the fastened figure.

You are watching: Predict the neutral organic product of the reaction.

Explanation:

By reaction an alkene (2-methylprop-1-ene) with an alcohol (methanol) in the presence of an acid it forms an ester (2-methoxy-2-methylpropane) v Markovnikov’s rule. First, a protonation of the alkene occurs wherein a tertiary carbocation is formed, climate the nucleophile (methanol) attacks the previously created carbocation, and finally ocurr the deprotonation the the hydrogen bound to the oxygen, thus developing the ester, in our instance the neutral essential product 2-methoxy-2-methylpropane.


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"7.46" is the correct bromheads.tv.

Explanation:

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The molar solubility the CaSO4 in water is 0 .67 gram per liter the solution. Calculation the Ksp.

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Ksp = 2.4 * 10⁻⁵

Explanation:

The equation because that the dissolution and dissociation of CaSO4 in water is offered as: CaSO₄ ---> Ca²⁺ + SO₄²⁻

The expression for the Ksp that the dissociation equation over is:

Ksp =

The molar proportion of the dissociated ions and also the solute is 1 : 1, this means that every 1 mole that CaSO₄ the dissolves produces 1 mole the Ca²⁺ and SO₄²⁻ each

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molar solubility of CaSO₄ = number of moles /liter the solution

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