Then, my question is just how to fix the inquiry 2? I"m in doubt what also to do. Can someone describe me, what come do?


The vectors that form a basis because that the column an are are certainly in the shaft space. Friend can choose one of these.

You are watching: For the matrix a below, find a nonzero vector in nul a and a nonzero vector in col a.



For the shaft space, pick any kind of (nonzero) column.

For the row space, pick any (nonzero) row.

For the null space, an alert that first and 3rd columns of $A$ room equal, which method that

$$A\beginbmatrix 1 \\ 0 \\ -1 \\ 0\endbmatrix = 0.$$


Other 보다 just using formulas, carry out you know the meanings of this words? To obtain a vector in the column space, take any type of one the the columns that the matrix. To acquire a vector in the row room take any one of the rows of the matrix. A vector in the null room is any type of vector, v, such that Av= 0. That"s the only non-trivial component of (2).


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